10 ... any polygon it is 2 less than the number of sides or vertices wince they are the same.
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17
7-3 = 4
Two triangles can be formed by the diagonals of one vertex of a four-sided polygon.
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.