The 5 can appear in any of the 4 positions, and for each of those 4 positions the other 3 positions can be filled by any of the other eight digits (1-4, 6-9).
→ 4 x 8 x 8 x 8 = 2048 different numbers with the 5 appearing exactly once.
Using the digits 1, 3, and 5 exactly once, you can create different 3-digit numbers by permuting these digits. The number of permutations of 3 distinct digits is calculated as 3! (3 factorial), which equals 6. Therefore, the different numbers you can create are: 135, 153, 315, 351, 513, and 531. Thus, there are 6 different numbers that can be formed.
the largest five digit number that can be formed using the digits 7 and 9 is 97,000
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
192, including ones containing repeat digits.
-1995
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
If the digits are all different then 18. Otherwise, 192.
the largest five digit number that can be formed using the digits 7 and 9 is 97,000
36
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
192, including ones containing repeat digits.
10,000
-1995
The number of 4 digit codes, using different digits, is 10*9*8*7 = 5040. However, computer passwords can, usually, have repeated digits and, if that is allowed, you can have 104 = 10000 codes.
The number of different 7 digit plates that can be formed where the digits are notrepeated and no zero appears as the first digit is: 544 320.Calculation:Number of different plates = 9 [9P6] = 9 [9!/(9-6)!] = 9x9x8x7x6x5x4 = 544 320.
how make the answer im don/now
The biggest number that can be formed with just those four digits once each, is 8641 - however - no number made from those digits can be divided by 9 because in order for a number to be exactly divisible by nine - the sum of the digits must also divide exactly by nine. The sum of the digits 6, 4 8 & 1 is 19 !Another Answer:-The above answer is absolutely correct.A possible solution is 61+8/4 = 63 and 7*9 = 63