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How many different three-digit whole numbers are possible using the digits 1 and 2 and 3 and 4 and 5?
Wiki User
∙ 2011-06-04 05:28:51
If repetition is allowed [such as 122 or 555], then there are 5³ = 125 possibilities.
Wiki User
∙ 2011-06-04 05:28:51
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How many ssn number combinations?
Interesting.Social Security numbers all have the form: (3 digits) - (2 digits) - (4 digits).That's 9 digits altogether. If you ignore the dashes, you get: xxx,xxx,xxx .With 9 places, there are 1 billion possible different numbers.
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
Start with a three-digit number in which the digits are all different Use the digits to make all possible two-digit numbers and obtain their sum Investigate?
The sum is 22 times the sum of the three digits.
How many different numbers can you make using 5 different digits?
89,999 different numbers i guess
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many different numbers can be formed with the digits 345?
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
How many ssn number combinations?
Interesting.Social Security numbers all have the form: (3 digits) - (2 digits) - (4 digits).That's 9 digits altogether. If you ignore the dashes, you get: xxx,xxx,xxx .With 9 places, there are 1 billion possible different numbers.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
Start with a three-digit number in which the digits are all different Use the digits to make all possible two-digit numbers and obtain their sum Investigate?
The sum is 22 times the sum of the three digits.
How many numbers are there between 100 and 999 in which all three digit numbers are different?
There are 9 possible numbers for the first digit (one of {1, 2, ..., 9}); with 9 possible digits for the second digit (one of {0, 1, 2, ..., 9} which is not the first digit)); with 8 possible digits for the third digit (one of {0, 1, 2, ..., 9} less the 2 digits already chosen); This there are 9 × 9 × 8 = 648 such numbers.
How many different numbers can you make using 5 different digits?
89,999 different numbers i guess
How many digits does a phone number have in it?
In the US and Canada, telephone numbers have 10 digits, including the area code. Other countries use phone numbers with different numbers of digits.
How many phone numbers are possible for one area code if the first four numbers are 202-1 in that order and the last three numbers are 1-7-8 in any order?
With the constraints you have listed, there are only 6 possible phone numbers:202-1178202-1187202-1718202-1781202-1817202-1871The first four digits are fixed, and there are six possible permutations of three different digits.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many number can be created with 15679?
It is possible to create infinitely many numbers, of infinitely many different lengths, using the digits of the given number. Using each of the digits, and only once, there are 5! = 120 different permutations.
How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?
Without repeats there are 4 × 3 = 12 possible 2 digit numbers. With repeats there are 4 × 4 = 16 possible 2 digit numbers.
