Wiki User
∙ 13y agoThere are three that I can see, there's clip, board and lip.
Wiki User
∙ 13y agoThere are 8P5 = 8*7*6*5*4 = 6720
(!7)/(!2.!2) =1260
tak-kee plasstic compnany prints a 2-letter code on each of its products. How many different 2-letters codes can be formed using the 26 letters of the alphabet if the two letters must be different?
The answer depends on how many letter tiles you have and which letters are on those tiles.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
There are 5*4*3 = 60 permutations.
9*8*7 / 2! / 3!
nkhnlk453
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
There are 8P5 = 8*7*6*5*4 = 6720
There are ten letters BUT there are 3 Ss and Ts and 2 Is. So the answer is 10!/(3!*3!*2!) = 50400
A - Z means you can use the whole alphabet, which usually contains 26 letters. So a one-letter code would give you 26 permutations. 2 letters will give you 26 x 26 permutations. A three letter code, finally, will give you 26 x 26 x 26 , provided you don't have any restrictions given, like avoiding codes formed from 3 similar letters and such.
420.
How many four-letter permutations can be formed from the letters in the word DECAGON?
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.