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How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many 5 letter permutations can be formed from the letters in vertical?
There are 8P5 = 8*7*6*5*4 = 6720
How many word formed using stapler?
The word "stapler" consists of 7 letters. By using all the letters, you can form several permutations, specifically 7! (factorial of 7) arrangements, which equals 5,040. However, if you're looking for meaningful words, the number will be significantly lower and depends on the dictionary used. Additionally, various shorter words can be formed from its letters.
How many different 7 letter words can be formed from the letters of the word college?
(!7)/(!2.!2) =1260
How many different ways can a president vice president and secretary be elected from a class of 32 students?
tak-kee plasstic compnany prints a 2-letter code on each of its products. How many different 2-letters codes can be formed using the 26 letters of the alphabet if the two letters must be different?
How many different 3 letter permutations can be formed from the letters in the word count?
There are 5*4*3 = 60 permutations.
How may different nine-letter permutations can be formed from the nine letters in the word isosceles?
9*8*7 / 2! / 3!
How many distrinct permutations can be formed using the letters of the word Tennessee?
nkhnlk453
How many different five letter permutations can be formed fron the letters of the word ditto?
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many different 7 letters permutations can be formed from 5 identical H's and two identical T's?
To find the number of different 7-letter permutations that can be formed from 5 identical H's and 2 identical T's, we use the formula for permutations of multiset: [ \frac{n!}{n_1! \times n_2!} ] where (n) is the total number of letters, and (n_1) and (n_2) are the counts of each type of letter. Here, (n = 7), (n_1 = 5) (for H's), and (n_2 = 2) (for T's). Thus, the calculation is: [ \frac{7!}{5! \times 2!} = \frac{5040}{120 \times 2} = \frac{5040}{240} = 21 ] Therefore, there are 21 different permutations.
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many 5 letter permutations can be formed from the letters in vertical?
There are 8P5 = 8*7*6*5*4 = 6720
How many Five letter word using letters a a g m m r?
To find the number of five-letter words that can be formed using the letters a, a, g, m, and m, we can use the formula for permutations of multiset. The total permutations of the letters is given by ( \frac{5!}{2! \times 2!} = \frac{120}{4} = 30 ). Therefore, there are 30 distinct five-letter arrangements that can be formed with the given letters.
How many permutations can be formed from the word statistics?
There are ten letters BUT there are 3 Ss and Ts and 2 Is. So the answer is 10!/(3!*3!*2!) = 50400
How many permutations are there in a 3-letter code which can use the letters from A to Z inclusive?
A - Z means you can use the whole alphabet, which usually contains 26 letters. So a one-letter code would give you 26 permutations. 2 letters will give you 26 x 26 permutations. A three letter code, finally, will give you 26 x 26 x 26 , provided you don't have any restrictions given, like avoiding codes formed from 3 similar letters and such.
