Of the first 100 positive numbers, 76 are divisible by the 3 smallest prime numbers. These are 3, 4, 5, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, and 100.
The smallest integer that is divisible by the first 10 positive integers (1 through 10) is known as the least common multiple (LCM) of those numbers. The LCM of 1 through 10 is 2520. This is found by taking the highest powers of all prime factors present in the factorizations of these integers. Thus, 2520 is the smallest integer divisible by all of them.
120
To find the smallest positive perfect square that is divisible by 2, 3, 5, and 7, we first determine the least common multiple (LCM) of these numbers. The LCM is (2^1 \times 3^1 \times 5^1 \times 7^1 = 210). For a number to be a perfect square, all prime factors must have even exponents. Thus, we square the LCM, yielding (210^2 = 44100). Therefore, the smallest positive perfect square that is divisible by 2, 3, 5, and 7 is 44100.
The least number that is divisible by the first 12 counting numbers (1 through 12) is known as the least common multiple (LCM) of those numbers. The LCM of 1 through 12 is 27720. This means that 27720 is the smallest number that can be evenly divided by each of the first 12 counting numbers.
The list of numbers that are divisible by three is infinite. The first four are: 3, 6, 9, 12 . . .
2520
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
The smallest integer that is divisible by the first 10 positive integers (1 through 10) is known as the least common multiple (LCM) of those numbers. The LCM of 1 through 10 is 2520. This is found by taking the highest powers of all prime factors present in the factorizations of these integers. Thus, 2520 is the smallest integer divisible by all of them.
11
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
2310
It is 2520.
2520
30, which is the smallest positive integer divisible by the first three primes: 2, 3 and 5.
the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.
120