shut up guys
4!=4x3x2x1=24
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
To calculate the number of license plate combinations using three letters and four numbers, we consider the possibilities for each part separately. There are 26 letters in the English alphabet, so for three letters, there are (26^3) combinations. For the four numbers, using digits 0-9, there are (10^4) combinations. Therefore, the total number of combinations is (26^3 \times 10^4), which equals 17,576,000 combinations.
all numbers have to be different 720 360 (6*5*4*3*2*1), * * * * * Wrong. Combinations do not have to be different. Those are permutations. There are only 6C4 = 6*5/(2*1) = 15 combinations.
There are 360 of them.
4!=4x3x2x1=24
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
252 combinations, :)
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
all numbers have to be different 720 360 (6*5*4*3*2*1), * * * * * Wrong. Combinations do not have to be different. Those are permutations. There are only 6C4 = 6*5/(2*1) = 15 combinations.
There are 360 of them.
There are 4,500 combinations.
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
7
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
64
There are infinitely many numbers and so infinitely many possible combinations.