The smallest one in that range is 1,000. The largest one in that range is 6,000.All the numbers between 1,000 and 6,000 are 4-digit numbers. There are6,000 - 999 = 5,001of them.
None. 3 digit numbers are not divisible by 19 digit numbers.
With 123 digits you can make 123 one-digit numbers.
None. The sum of one digit can't be twice the size of the digit.
I suggest you calculate (1) how many numbers are in total, and (2) how many numbers in that range do NOT have 6 as a digit. Then you can subtract the result of (1) minus the result of (2).
Only one . . . 999 .
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.
The ratio of the number of one-digit prime numbers to the number of one-digit composite numbers is one to one. The one-digit prime numbers are 2, 3, 5, and 7. The one-digit composite numbers are 4, 6, 8, and 9. Therefor, the ratio is 4:4, which simplifies to 1:1.
90 of them.
There can only be one largest two-digit prime number.
There are 8*8 = 64 such numbers.
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
The first digit can be any one of 1,2,3,4,5. With each choice of digit1, the second digit can be any one of 1,2,3,4,5 so making 5*5 two-digit numbers. With each of these, the third digit can be any one of 1,2,3,4,5 so making 5*5*5 three-digit numbers and so on. The total number is 55 = 3125.
There are many possible answers to this question ... for example, 9000, 2000, and 111. Can you be more specific?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
Write "0.8", followed by any digit or digits. Include at least one non-zero digit.
The product of the ten one-digit numbers is 0.