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Subjects>Math>Math & Arithmetic

How many of each digit in numbers 1 through 50?

Anonymous

∙ 12y ago

Updated: 12/31/2024

Well honey, in numbers 1 through 50, each digit from 0 to 9 appears 5 times. It's simple math, darling. Just divide the total number of digits by 10 and you'll get your answer. Now go impress someone with your newfound knowledge, you're welcome!

BettyBot

∙ 3mo ago

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More answers

1 to 4: 15 times each

5: 6 times

6 to 9: 5 times each

Wiki User

∙ 12y ago

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Q: How many of each digit in numbers 1 through 50?

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Continue Learning about Math & Arithmetic

How many 2-digit numbers contain the digit?

It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.

How many 4 digit numbers have 6 as their second digit?

There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.

If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?

Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.

How many different three digit numbers can be written using the digits 1 through 9?

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.

How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?

10!/3! = 604800 different combinations.

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Related Questions

How many 2-digit numbers contain the digit?

It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.

How many 4 digit numbers have 6 as their second digit?

There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.

How many 3 digit numbers are under 500?

The 3 digit numbers under 500 are 100 through 499.

How many different 9 digit combination can be made using numbers zero through nine?

Just think of how many possibilities you have for each digit. 10x9x8x7x6x5x4x3x2 or 10 factorial is 3 628 800.

How many different three digit numbers can be formed from the digits 0 through 9 if the first digit must be odd and the last digit must be even?

5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.

If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?

Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.

How many 5 digit combos in 30 numbers?

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

How many different three digit numbers can be written using the digits 1 through 9?

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.

How many 10 digit numbers can be formed using each digit once?

ten factorial = 10! = 3,628,800

How many three digit numbers containing 3 7 and 9 using each digit once?

six

How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?

10!/3! = 604800 different combinations.

How many 4 digit numbers can you make using numbers 0 through 9 With repetition?

10999

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