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How many 2-digit numbers contain the digit?
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many different three digit numbers can be written using the digits 1 through 9?
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?
10!/3! = 604800 different combinations.
How many 2-digit numbers contain the digit?
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How many 3 digit numbers are under 500?
The 3 digit numbers under 500 are 100 through 499.
How many different 9 digit combination can be made using numbers zero through nine?
Just think of how many possibilities you have for each digit. 10x9x8x7x6x5x4x3x2 or 10 factorial is 3 628 800.
How many different three digit numbers can be formed from the digits 0 through 9 if the first digit must be odd and the last digit must be even?
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many 10 digit numbers can be formed using each digit once?
ten factorial = 10! = 3,628,800
How many three digit numbers containing 3 7 and 9 using each digit once?
six
How many different three digit numbers can be written using the digits 1 through 9?
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?
10!/3! = 604800 different combinations.
How many 4 digit numbers can you make using numbers 0 through 9 With repetition?
10999
