There is insufficient information in the question to properly answer it. You did not specify what kind of input sets are involved. Please restate the question.
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There are 1024 different outcomes, so too many to list.
The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.The answer depends on what the outcome comprises.If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.
According to my calculations, with the first four included. It should be 33,396 combinations
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