Ok, sounds like a trick question. Obviously, there can be only one result, either heads or tails. Generally, when we consider the set of possible outcomes, we would say a coin flip has 2: a head and a tail. If I really want to complicate the matter, I could include that the coin might land on an edge. Don't think its realistic to include landing on an edge as an outcome. Ok, sounds like a trick question. Obviously, there can be only one result, either heads or tails. Generally, when we consider the set of possible outcomes, we would say a coin flip has 2: a head and a tail. If I really want to complicate the matter, I could include that the coin might land on an edge. Don't think its realistic to include landing on an edge as an outcome.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
9
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
24 possible outcomes.
There are eight (8).
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are 26 = 64 possible outcomes.
There are 25 = 32 possible outcomes.
32
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.
I believe there would be 11 possible outcomes!
5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.
9
18 outcomes
8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.
Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.