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The answer depends on what the outcome comprises.

If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).

If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.

There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.

The answer depends on what the outcome comprises.

If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).

If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.

There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.

The answer depends on what the outcome comprises.

If the outcome is simply a count of H and T, then there are 12 outcomes: 0H, 1H, 2H, ... 10H and 11H (with the corresponding number of T in each case).

If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.

There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.

The answer depends on what the outcome comprises.

If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.

There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.

More answers

The answer depends on what the outcome comprises.

If the result for each coin is recorded individually, there are 211 = 2048 possible outcomes.

There are many other results that can be defined, and the number of possible outcomes will vary according to the definitions.

Q: How many possible outcomes would there be if eleven coins were tossed at once?

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2*2*2*2 = 16

Two

The total number of outcomes is 2^5 = 32.

Since each coin would have the outcome with Heads and Tails: Then among the 32 coins, we can have the possible outcomes from no Heads, 1 Head, 2 Heads, ....... , 31 Heads, 32 Heads. Therefore we would have 33 outcomes.

There are 48 possible outcomes and I have no intention of listing them all. They are all of the form CCCD where C = H or T, and D takes the numeric values from 1 to 6.

Related questions

9

I believe there would be 11 possible outcomes!

8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.

24 possible outcomes.

There are eight (8).

Eight of them.

The possible outcomes areHH, HT, TH and TT.

2*2*2*2 = 16

Heads ( H ) Tails ( T ) HH , TT , HT , TH

Two

There are eight possible outcomes: HHH, HHT, HTT, HTH, THT, TTT, TTH, THH.

9, you just have to multiply for problems like this