Answer: there are five distinct letters in the word 'smart'. However we may rearrange them, every rearrangement will consist of all and only those five elements. The case here is just the same as if we were wanting to determine how many different ways we could seat 5 people in a five-seat row of chairs. In the first chair we could seat any one of the five--and just for fun we'll imagine this is a group of five of my former girlfriends [S]usan, [M]olly, [A]shlee, [R]ebecca, and (yes, it's a stretch) Kasey [T.]. So any one of the five chicks can take the first seat, which is to say there are five possible outcomes for seat number one. Now regardless of who the first girl is, once she sits down there are four girls left, any any one of whom can sit down next to her in seat number 2. Suppose Ashlee takes the first seat. Then there are four possibilities for who sits next to her: Susan, Molly, Rebbecca, or Kasey T. But any one of those girls could just as easily have taken have taken
10! permutations of the word "Arithmetic" may be made.
There are 7 factorial, or 5040 permutations of the letters in the word NUMBERS.
There are 195 3-letter permutations.
There are 5040.
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
39916800 permutations are possible for the word INFORMATION.
10! permutations of the word "Arithmetic" may be made.
There are 8! = 40320 permutations.
There are 6! = 720 permutations.
If you mean permutations of the letters in the word "obfuscation", the answer is 1,814,400.
There are 7 factorial, or 5040 permutations of the letters in the word NUMBERS.
There are 195 3-letter permutations.
For the first letter, you can have any of 5 choices. Then for the next, you can have any of four. Then for the next, three and so on. Thus the number of permutations can be calculated by 5x4x3x2x1. Doing this gives 120. Therefore the number of permutations of the letters in the word smart is 120.
There are 30 of them.
2
There are 12.
24.