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For the first letter, you can have any of 5 choices. Then for the next, you can have any of four. Then for the next, three and so on. Thus the number of permutations can be calculated by 5x4x3x2x1. Doing this gives 120.
Therefore the number of permutations of the letters in the word smart is 120.
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How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
In how many different ways can the letters of the word ARISE be arranged?
The number of different ways the letters of a word can be arranged, when all the letters are different, is the same as the number of permutations of those letters. In this case, the answer is 5!, or 120.
How many ways can you rearrange the letters in the word pencil?
To calculate the number of ways the letters in the word "pencil" can be rearranged, we first determine the total number of letters, which is 6. Since there are two repeated letters (the letter 'e'), we divide the total number of letters by the factorial of the number of times each repeated letter appears. This gives us 6! / 2! = 360 ways to rearrange the letters in the word "pencil."
How many ways to rearrange the letters of the word 'CHEESE'?
CHEESE cheese has 6 letters in it. if you have a word with different letters, you do the factorial of the number of letters there are. but you can not do that in this word. since it has 3 E's, then you mut do 6!(factorial) divided by 3! then the answer would be 120
How many arrangements of the letters in the word SCHOOLS are there?
The number of permutations of the letters in the word SCHOOLS is the number of permutations of 7 things taken 7 at a time, which is 5040. However, since two of the letters, S and O, are duplicated, the number of distinct permutations is one fourth of that, or 1260.
How many permutations are in the word permutation?
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400
What is the number of distinguishable permutation of the letters in the word September?
September has 9 letter, of which one appears 3 times. So the number of distinct permutations is 9!/3! = 120,960
How do you make a good sentence with the word permutation?
i am a permutation is a awesome answer
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
Which is better- word-smart or number-smart?
Number smart is better
Can the word smart create more five letters word?
Yes. Marts Trams
The word smart can be created using five letters from the word barnstorm?
this is true... because bARnSTorM
What is it called when letters of a word are used to form other words?
Hello,That is called a Permutation,it can also be done with number Example. Letter Permutation abc acb bac bca cab cba Numerical Permutation 123 132 213 231 321 312 Are you thinking of an acrostic instead?
In how many different ways can the letters of the word coniohser be arranged?
Coniohser has 9 letters. So the solution is permutation of nine that means 1*2*3*4*5*6*7*8*9 =362880
Can the word 'smart' can be created using five letters from the word 'barnstorm'?
Yes, the word "smart" can be created using five letters from "barnstorm." You need to remove the b, n, o, and one r. Then you just mix up the remaining letters, which should be a, s, t, r, and m.
How many permutation of umbrella?
There are 20160 permutations of the word.
What is the number of distinguishable permutations of the letters in the word GLASSES?
The solution is count the number of letters in the word and divide by the number of permutations of the repeated letters; 7!/3! = 840.
