The answer depends on the number of point. One point - as the question states - cannot be non-collinear. Any two points are always collinear. But three or more points will define a plane. If four points are non-coplanar, they will define four planes (as in a tetrahedron).
One.exactly one
just one
Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
In geometry, a single point, such as Point A, is included in an infinite number of different planes. Any three non-collinear points define a unique plane, and since a point can be part of many combinations with other points, there are countless planes that can be formed through Point A. Therefore, the answer is that Point A is included in infinitely many planes.
10!
1 line cause every plane contains atleast 3 or more noncollinear points
exactly one and only one.
3 non-collinear points define one plane.
One.exactly one
1, exactly 1 plane will
just one
Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
Ten.Each angle is determined by two rays, so the answer is equivalent to the number of combinations of 2 out of 5 = 5*4/(2*1) = 10
Only one plane can pass through 3 non-collinear points.
One.
10!
1