exactly one and only one.
Only one plane can pass through 3 non-collinear points.
Any Euclidean plane has infinitely many points.
Infinitely many planes may contain the same three collinear points if the planes all intersect at the same line.
I have a feeling that I'm wrong but i guess that 2 planes can pass through 2 points
exactly nine planes! * * * * * I would have said 4 - corresponding to the four faces of a tetrahedron. Of course, non-collinear does not mean non-coplanar so all four points could be in the same single plane!
1 line cause every plane contains atleast 3 or more noncollinear points
3 non-collinear points define one plane.
One.exactly one
1, exactly 1 plane will
just one
The answer depends on the number of point. One point - as the question states - cannot be non-collinear. Any two points are always collinear. But three or more points will define a plane. If four points are non-coplanar, they will define four planes (as in a tetrahedron).
Only one plane can pass through 3 non-collinear points.
10!
Three noncollinear points A, B, and C determine exactly three lines. Each pair of points can be connected to form a line: line AB between points A and B, line AC between points A and C, and line BC between points B and C. Thus, the total number of lines determined by points A, B, and C is three.
Any Euclidean plane has infinitely many points.
3
one