3 non-collinear points define one plane.
8
1, exactly 1 plane will
3 or more
Three.
A triangle
8
1 line cause every plane contains atleast 3 or more noncollinear points
exactly one and only one.
One.exactly one
1, exactly 1 plane will
The answer depends on the number of point. One point - as the question states - cannot be non-collinear. Any two points are always collinear. But three or more points will define a plane. If four points are non-coplanar, they will define four planes (as in a tetrahedron).
just one
Three noncollinear points ( A ), ( B ), and ( C ) determine exactly three lines: line ( AB ), line ( BC ), and line ( AC ). Each pair of points defines a unique line, and since the points are noncollinear, no two lines coincide. Thus, the total number of lines determined by points ( A ), ( B ), and ( C ) is three.
Only one plane can pass through 3 non-collinear points.
Three noncollinear points A, B, and C determine exactly three lines. Each pair of points can be connected to form a line: line AB between points A and B, line AC between points A and C, and line BC between points B and C. Thus, the total number of lines determined by points A, B, and C is three.
4 planes.
A real-life example of noncollinear points can be found in the layout of a triangular park. If you consider three trees planted at different corners of the park, those trees represent noncollinear points because they do not lie on the same straight line. Each tree's position forms a distinct vertex of the triangle, illustrating how noncollinear points can create shapes in a spatial context.