the midpoint of
4b
b+b+b+c+c+c+c =3b+4c
3b
To travel from point B to point C is 550 miles. The return trip from point C back to point B is the same distance, so it also takes 550 miles. Therefore, the total distance for the round trip from point B to point C and back to point B is 550 miles + 550 miles, which equals 1100 miles.
A grade point average of 3.35 is about a B plus on a 4.0 scale. On this scale, a B grade is 3.0 and a B plus starts at about 3.33.
it takes N-miles from point A to Point B and so on and so on
the midpoint of
between A and B
4b.
The point (1, 13) lies on y = ax^2 + bx + 12 So the coordinates of the point satisfy the equation. 13 = a + b + 12 => a + b = 1 .. .. .. .. .. .. .. .. .. (1) The stationary point of the curve is reached when dy/dx = 0: that is 2ax + b = 0 at (1, 12) this gives 2a + b = 0 .. .. .. (2) Solving (1) and (2) gives a = -1, b = 2
4b
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
a-b+a-b+2b+a = 4a
3b
To travel from point B to point C is 550 miles. The return trip from point C back to point B is the same distance, so it also takes 550 miles. Therefore, the total distance for the round trip from point B to point C and back to point B is 550 miles + 550 miles, which equals 1100 miles.