There are 18, but only 7 primitive ones. The rest are similar to the primitive triangles : for example (15, 50, 25) is similar to (3, 4, 5).
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A = bh/2 2A = bh 2(16) = bh 32 = bh I would like to use integers, so the possibilities for the base and height are 1 and 32, 2 and 16, 4 and 8 units, or vice verse. Always, it's your choice how to use them in order to draw different kind of triangles, such as right, scalene, or obtuse triangles.
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Triangle with sides 4,5 and 6 units Quadrilateral with sides 1,3,5 and 6 units Pentagon with sides of 1,1,2,5 and 6 units
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There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
An equilateral triangle with sides of 10/3 units, an isosceles triangle with 2 sides of a units and the third of 10-2a units (for any a<5), or several options for scalene triangles. A square or rhombus with sides of 2.5 units, or a rectangle or parallelogram with sides of b and 5-b units etc A regular pentagon with sides of 2 units. And so on.
The sides of the square are 9 units so the sides of the triangles are 9, 10.5 and 10.5. This makes the perimeter of the shape 8 x 10.5 ie 84 units.
Three examples: 10, 10 and 5; 9,9 and 7; 8, 8 and 9
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Let's ignore 'triangles' with sides of length zero. I assume that you mean triangles with sides of whole-number length; otherwise, the possibilities are infinite. The sides have to add to five. There are only two ways of doing this: 1 + 1 + 3 1 + 2 + 2 Both of these possibilities satisfy the other constraint mentioned in the question.
According to the "3-4-5" law of right triangles, if the two sides of the triangle are 3 units and 4 units, the hypotenuse must be 5 units. So a diagonal must be 15 inches. The sides are 3 * 3 and 3 * 4, so the diagonal is 3 * 5.
A = bh/2 2A = bh 2(16) = bh 32 = bh I would like to use integers, so the possibilities for the base and height are 1 and 32, 2 and 16, 4 and 8 units, or vice verse. Always, it's your choice how to use them in order to draw different kind of triangles, such as right, scalene, or obtuse triangles.
I assume the corresponding sides are AB and EF, and EF is a side of the larger (second) triangle. scale factor 3 means each length of the second is 3 times as long as the first. ⇒ if AB = 6 units, EF = 3 x 6 units = 18 units.
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Surface area is measured in square units.