answersLogoWhite

0

None because without an equality sign the given expression is not an equation and so therefore no solutions are possible.

User Avatar

Wiki User

7y ago

Still curious? Ask our experts.

Chat with our AI personalities

FranFran
I've made my fair share of mistakes, and if I can help you avoid a few, I'd sure like to try.
Chat with Fran
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao

Add your answer:

Earn +20 pts
Q: How many solutions are there to the equation x3 - 7 0?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

What is the equation for the sum of three consecutive integers is negative 87?

Since there are three numbers involved in the answer, the equation needs to have three solutions which makes it somewhat complicated. x3 + 87x2 + 1739x + 24360 = 0


How many solutions will the equation 25 equals 2x squared-6x have?

2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34


How can you tell how many solutions a quadratic equation will have without solving it?

A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.


How do I write an equation for a sequence that isn't linear or exponential?

A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)A polynomial equation: ax4+ bx3+ cx2+ dx + e = 0A trigonometric equation: sin(3x+2) = 0 Combinations: cos(x3+ e2x) = ln(x)


Can any number divided by itself equal to the square of the original number?

As an equation, x/x = x2, or x2 = x/x. Multiplying both sides by x: x3 = x. Put everything on the left side: x3 - x = 0. Factoring the left part: x(x2 - 1) = 0, or x(x+1)(x-1) = 0. This has the solutions 0, 1, -1. However, 0 doesn't make sense in the original equation - it seems that multiplying with "x" introduced an extra solution.The remaining solutions, 1 and -1, fit the original specification.