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It's a simple second-degree equation in 'A' . Like any second-degree equation, it has two solutions. They are +14 and -14 .
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
Are you sure the equation is not: -3x2 - 2x + 5 = 0? Which is the same as 3x2 + 2x - 5 = 0 which factorises into (3x + 5)(x - 1) with solutions x = 1 and x = -5/3 = -1 2/3 ~= -1.67. As stated there are no real solutions to the equation, only complex solutions: x = -1/3 + i sqrt(14)/3 and x = -1/3 - i sqrt(14)/3
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula