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It's a simple second-degree equation in 'A' . Like any second-degree equation, it has two solutions. They are +14 and -14 .
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
Are you sure the equation is not: -3x2 - 2x + 5 = 0? Which is the same as 3x2 + 2x - 5 = 0 which factorises into (3x + 5)(x - 1) with solutions x = 1 and x = -5/3 = -1 2/3 ~= -1.67. As stated there are no real solutions to the equation, only complex solutions: x = -1/3 + i sqrt(14)/3 and x = -1/3 - i sqrt(14)/3
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
It's a simple second-degree equation in 'A' . Like any second-degree equation, it has two solutions. They are +14 and -14 .
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
why will the equations x+14=37 and x-14=37 have different solutions for x
2x + 14 = 0Subtract 14 from each side of the equation: 2x = -14Divide both sides of the equation by 2: x = -7You can also obtain solutions to equations by visting wolframalpha.com. Enter solve 2x+14=0, for example. You can click on the 'step-by-step' button to see how the equation was solved.
An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3
The parallel equation will have the same slope but with a different y intercept
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Are you sure the equation is not: -3x2 - 2x + 5 = 0? Which is the same as 3x2 + 2x - 5 = 0 which factorises into (3x + 5)(x - 1) with solutions x = 1 and x = -5/3 = -1 2/3 ~= -1.67. As stated there are no real solutions to the equation, only complex solutions: x = -1/3 + i sqrt(14)/3 and x = -1/3 - i sqrt(14)/3
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
The symbol of carbon-14 (not equation) is 14C.