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2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
P=2w+2l
p=2l+2w a=wl
you have two equations with two unknowns, length and width let W = width and L = length 2W - 4 = L (1) The perimeter is 2L + 2W 2L + 2W = 34 (2) rearrange (1) and (2) 2W - L = 4 2W +2L = 34 multiply (1) both sides by 2 4W - 2L = 8 2W + 2L =34 add equations 6W = 42 W = 7 solve L from (2) by substituting W = 7 L = 10
p=2l+2w 34= 2(10) +2w 34= 20 +2w 14= 2w w=7