Study guides

☆☆

Q: How many time does the digit 6appear in the numbers 1 to 65?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The digit appears eleven time from 1 to 100.

This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.

Let's solve it a step at a time. For the first digit, how many choices do you have? 9 You can choose 1..9 but not 0, so that's nine choices for the most significant digit. For the second digit, how many choices do you have? 10 It can be 0..9. For the third digit, you also have 10 choices. Choosing one digit doesn't limit your choices for other digits and mirrored numbers (e.g. 123 and 321) are different, so all choices make a unique number. So the total is the product of our three choices: 9x10x10

Starting with the number just before the "decimal/binary" point and going left: you leave the first digit as it is, add 2 times the digit to its left, add 4 times the digit to its left, add 8 times the digit to its left, and so on to the end. The multiple is doubled each time. If you have digits to the right of the point, you add 1/2 times the first digit add 1/4 times the digit to its right, add 1/4 times the digit to its right, and so on to the end. The multiple is halved each time. The grand total is the equivalent decimal number.

There are 4536 of them and I have neither the time nor the inclination to list them. This assumes the starting digit is not 0. If 0 is allowed as the first digit, there will be 5040 such numbers. Since each digit is used only once, this is a problem without replacement means that an outcome cannot be included more than once. In this case, the first event does affect the possibilities for the second event. These event are dependent. So the number could have any of these forms: 1_ _ _ , 2_ _ _ , 3_ _ _ , 4_ _ _ , 5_ _ _ , 6_ _ _ , 7_ _ _ , 8_ _ _ , 9_ _ _ . There are 9 choices for the thousands digit: 1, 2, 3, 4, 5, 6, 7, 8, or 9. After the thousands digit is chosen, 9 choices are left for the hundreds digit After the hundreds digit is chosen, 8 choices are left for the tens digit. After the tens digit is chosen, 7 choices are left for the units digit. Then, we have (9 * 9 * 8 * 7) 4536 numbers.

Related questions

The digit appears eleven time from 1 to 100.

first digit time second digit and second digit times first digit then repeat

Definitely earlier than the year 2000. In April 2000, Portsmouth moved from six-digit local numbers to eight-digit numbers, as well as changing to the new, short area code of 023. (For example, Portsmouth City Council's number changed from 822251 to 92822251.) Instructions at the time referred only to how to convert six-digit local numbers to eight-digit numbers, so it is reasonable to assume that no five-digit numbers remained at that time.

Prior to the conversion to area code 029 with 8-digit local numbers in the Big Number Change in 2000, Cardiff was area code 01222 with 6-digit local numbers. If you go back in time, it is quite likely that Cardiff had 5-digit local numbers, and may also have had a mix of 5- and 6-digit numbers for some time.

It's how many times you have died.

1

24 = 4*3*2*1 of them

24

In such cases, you should compare one digit at a time, from left to right, until you find a digit that is different in the two numbers. That is, compare the first digit (after the decimal period) with the first digit, the second digit with the second digit, etc.

This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.

Let's solve it a step at a time. For the first digit, how many choices do you have? 9 You can choose 1..9 but not 0, so that's nine choices for the most significant digit. For the second digit, how many choices do you have? 10 It can be 0..9. For the third digit, you also have 10 choices. Choosing one digit doesn't limit your choices for other digits and mirrored numbers (e.g. 123 and 321) are different, so all choices make a unique number. So the total is the product of our three choices: 9x10x10

These numbers are selections from the numbers from 100 to 999. That's 9 choices for the first digit. Each time, the second digit has 9 choices (0 to 9 excluding the hundreds digit), and then the last digit has 8 choices. Total is then 9x9x8 = 648

People also asked