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Let's solve it a step at a time.
For the first digit, how many choices do you have? 9
You can choose 1..9 but not 0, so that's nine choices for the most significant digit.
For the second digit, how many choices do you have? 10
It can be 0..9.
For the third digit, you also have 10 choices.
Choosing one digit doesn't limit your choices for other digits and mirrored numbers (e.g. 123 and 321) are different, so all choices make a unique number.
So the total is the product of our three choices: 9x10x10
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How many 3 digit numbers divisible by 9 can be formed from the digits 0123456789?
There are 76 such numbers. Eight more if you allow numbers to start with 0.
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many 3-digit numbers can be formed using 0123456789 when repetition is not allowed?
-123456786
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
What is the number of possible 9 digit social security numbers if the digits can't be repeated?
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
How many 3 digit numbers divisible by 9 can be formed from the digits 0123456789?
There are 76 such numbers. Eight more if you allow numbers to start with 0.
What is the smallest 10-digit number with no repeated digits?
0123456789
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
What is the smallest digit can be formed without repeating any digit?
id say, 0123456789. but depends how many digits you can have
How many six digit numbers can be formed using the digits 0123456789 Example equals 123456 or 098765?
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
What is the highest 5 digit even number to be made out of 0123456789?
If the numbers are not repeated then the highest 5 digit even number to be made out of 0123456789 is : 98764.
How many possible 3 digit numbers can be made using the digits 604?
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
How many numbers are there between 100 and 999 in which all three digit numbers are different?
There are 9 possible numbers for the first digit (one of {1, 2, ..., 9}); with 9 possible digits for the second digit (one of {0, 1, 2, ..., 9} which is not the first digit)); with 8 possible digits for the third digit (one of {0, 1, 2, ..., 9} less the 2 digits already chosen); This there are 9 × 9 × 8 = 648 such numbers.
What is the probability of three digit numbers without repeated digits with numbers 0123456?
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
How many digits can be the product of two digit numbers have to give examples to support your answer?
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many 4 digit numbers are possible with no two numbers being adjacent?
There are 2941 4-digit numbers such no two of its digits differ by 1.
