An 18-gon, also known as an octadecagon, has 18 sides. To find the number of triangles in an n-gon, you can use the formula (n-2)C3, where C represents a combination. Plugging in n=18, we get (18-2)C3 = 16C3 = 16! / (3!(16-3)!) = 16! / (3! * 13!) = 161514 / 321 = 560. Therefore, an 18-gon has 560 triangles.
To find the number of triangles that can be formed in an 18-gon, you can use the formula for combinations: ( C(n, k) ), where ( n ) is the number of vertices and ( k ) is the number of vertices needed to form a triangle (which is 3). For an 18-gon, this is calculated as ( C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816 ). Therefore, there are 816 triangles that can be formed from the vertices of an 18-gon.
There are 18 sides
To find the number of diagonals in an 18-gon, you can use the formula ( D = \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an 18-gon, this gives ( D = \frac{18(18-3)}{2} = \frac{18 \times 15}{2} = 135 ). Therefore, an 18-gon has 135 diagonals.
(18-2)*180 = 2880 degrees
An 18-gon, or 18-sided polygon, has a total of 1800 degrees. This is calculated using the formula for the sum of the interior angles of a polygon, which is ((n - 2) \times 180) degrees, where (n) is the number of sides. For an 18-gon, it would be ((18 - 2) \times 180 = 16 \times 180 = 2880) degrees. Each interior angle of a regular 18-gon would therefore be 100 degrees.
18 triangles can be found in a 20-agon
To find the number of triangles that can be formed in an 18-gon, you can use the formula for combinations: ( C(n, k) ), where ( n ) is the number of vertices and ( k ) is the number of vertices needed to form a triangle (which is 3). For an 18-gon, this is calculated as ( C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816 ). Therefore, there are 816 triangles that can be formed from the vertices of an 18-gon.
There are 18 sides
18
It has 18 interior angles.
To find the number of diagonals in an 18-gon, you can use the formula ( D = \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an 18-gon, this gives ( D = \frac{18(18-3)}{2} = \frac{18 \times 15}{2} = 135 ). Therefore, an 18-gon has 135 diagonals.
(18-2)*180 = 2880 degrees
18 triangles
11- undecagon 12- dodecagon 13- 13-gon 14- 14-gon 15- 15-gon 16- 16-gon 17- 17-gon 18- 18-gon 19- 19-gon 20- 20-gon
An 18-gon, or 18-sided polygon, has a total of 1800 degrees. This is calculated using the formula for the sum of the interior angles of a polygon, which is ((n - 2) \times 180) degrees, where (n) is the number of sides. For an 18-gon, it would be ((18 - 2) \times 180 = 16 \times 180 = 2880) degrees. Each interior angle of a regular 18-gon would therefore be 100 degrees.
18. If a polygon has n sides, then it has n-2 triangles.There are 18 triangles in a 20 sided polygon.
The question makes no sense since a 18-gon cannot be added. You can add the measures of its interior or exterior angles, or the lengths of its sides, its diagonals and so on. But there is no such thing as a "sum of 18-gon".