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How many ways can 4 people be chosen from a group of 9and is this a combination or permutation?
it is a combination: 9!/4!=9 x 8 x 7 x 6
How many ways can a president vice president and secretary be chosen for a committee of 9 people?
There are 9*8*7 = 504 ways.
How many ways can 4 people be chosen from a group of 17?
You can choose 4 people in (17 x 16 x 15 x 14) = 57,120 ways.But there are (4 x 3 x 2) = 24 ways to pick the same 4 people, so there are only57,120/24 = 2,380 different groups of 4 people that you can end up with.
How many different ways can 5 people be selected from a group of 18?
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
In how many ways can 4 people be chosen from a group of 12 people and arranged in a straight line?
First in line can be any of the 12, second can be any of the remaining 11, third any of 10 and fourth any of 9 so 12 x 11 x 10 x 9 ie 11880 different ways
How many ways can a group of 7 people be chosen from a class of 15?
It is: 15C7 = 6435 combinations
How many ways can 4 people be chosen from a group of 9and is this a combination or permutation?
it is a combination: 9!/4!=9 x 8 x 7 x 6
How many ways can 2 people be chosen from a class of 20?
20C2 = 190
How many ways can a president vice president and secretary be chosen for a committee of 9 people?
There are 9*8*7 = 504 ways.
How many different ways can a president vice president and a secretary be chosen from a group of 15 people?
The answer is 15 * 14 * 13 = 15 P 3 = 780 IF you assume that no one person can hold two offices at once and that all in the group are qualified for any office.
How many ways can 4 people be chosen from a group of 17?
You can choose 4 people in (17 x 16 x 15 x 14) = 57,120 ways.But there are (4 x 3 x 2) = 24 ways to pick the same 4 people, so there are only57,120/24 = 2,380 different groups of 4 people that you can end up with.
How many different ways can 5 people be selected from a group of 18?
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
How many ways can a group of 3 students be chosen from a class of 30 students?
Well, honey, there are 30 students in the class, and you want to choose a group of 3. So, you're looking at a classic combination situation. The formula for combinations is nCr = n! / r!(n-r)!, so in this case, it's 30C3 = 30! / 3!(30-3)! = 4060 ways to choose those 3 lucky students. It's like picking the winning lottery numbers, but with fewer tears and more math.
In how many ways can 4 people be chosen from a group of 12 people and arranged in a straight line?
First in line can be any of the 12, second can be any of the remaining 11, third any of 10 and fourth any of 9 so 12 x 11 x 10 x 9 ie 11880 different ways
How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?
40 x 39 x 38 x 37 = 2193360
How many ways can 2 candies be chosen out of 5 candies?
10
In how many ways can a committee of three men and four women be formed from a group of 10 men and 10 women?
I'm going with 25,200 3 men out of 10 may be chosen in 10C3 ways = 10 ! / 3! 7 ! = 120 ways. 4 women may be chosen out of 10 in 10C4 = 10 ! / 4! 6! ways = 210 ways. Therefore, a committee with 3 men and 4 women can be formed in 120 x 210 = 25,200 ways.
