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The first question can be any one of the 10. For each of these . . .
The second question can be any one of the remaining 9. For each of these . . .
The third question can be any one of the remaining 8.

Total number of ways to choose 3 questions = (10 x 9 x 8) = 720 ways.

But the same 3 questions can be chosen in any one of 6 sequences.

So the number of different sets of 3 questions is only 720/6 = 120 .

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Q: How many ways can a student choose 3 questions from 10 questions?
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