Approx 904.8 cubic inches.
pi*r^2*h gives the volume of a foot long one inch pipe. Radius is 0.5 inches, height is 1 foot/12 inches. So the volume is 9.42 cubic inches. 9.42 (cubic inches) = 0.0407792208 US gallons
This pipe can hold up to 0.5 cubic foot or 3.7 gallons of water.
twelve inches or 12 inch.
12 inch = 1 foot 48 inch = 4 feet.
To calculate the weight of dry sand in a 1-foot long pipe with a 2-inch diameter, first find the volume of the pipe. The volume ( V ) is given by the formula ( V = \pi r^2 h ), where ( r ) is the radius (1 inch or 0.0833 feet) and ( h ) is the height (1 foot). The volume calculates to approximately 0.174 cubic feet. Given that dry sand weighs about 100 pounds per cubic foot, the total weight of the sand would be approximately 17.4 pounds.
One foot of 3 inch pipe will hold approximately 0.625 gallons of water.
This cylinder will hold up to 19.65 gallons of water.
pi*r^2*h gives the volume of a foot long one inch pipe. Radius is 0.5 inches, height is 1 foot/12 inches. So the volume is 9.42 cubic inches. 9.42 (cubic inches) = 0.0407792208 US gallons
Volume of a cylinder = (pi) (radius)2 (length)Volume = (pi) (0.25-ft)2 (20-ft) = 1.25 (pi) cubic feet = 3.927 cubic feet = 29.376 gallons (rounded)
About 0.35 cubic feet or about 2.6 gallons.
The volume is 0.7854 cubic feet.
This pipe can hold up to 0.5 cubic foot or 3.7 gallons of water.
5 foot an inch and a half
twelve inches or 12 inch.
1 foot =12 inch; 4500 inch = 375 ft
A 1-foot length of a pipe with an 1-inch internal diameter will hold pi*r2*h cubic inches where r = 0.5, h = 12 So 9.42 cubic inches.
Divide the diameter by two - and you'll have your answer !