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∙ 12y agoA change in water temperature with no change of state requires one calorie per gram of pure water per degree Celsius.
90° - 15° = 75°
80 g x 75° C x 1 cal/g/°C = 6000 cal = 6 kcal
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∙ 12y agoHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water(1 cal/gm)=5x1x(50-25) =125 cal
8.200 J
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
32 Degrees Fahrenheit 0 Degrees Celsius
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
Q=mcΔT Q=14 x 4200 x 21.6 Q=1270080J
It takes 6 SI calories to raise one liter of water by 6 degrees Celsius.
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.
The heat needed can be calculated using the formula: Q = mc∆T, where Q is the heat, m is the mass of water, c is the specific heat capacity of water (4186 J/kg°C), and ∆T is the change in temperature. Plug in the values to find the heat needed.
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
Water boils at 100 degrees Celsius, so 87 degrees is 13 degrees away from boiling.
The amount of heat necessary to raise 1 gram of a substance by 1 degree Celsius is known as?