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A change in water temperature with no change of state requires one calorie per gram of pure water per degree Celsius.

90° - 15° = 75°

80 g x 75° C x 1 cal/g/°C = 6000 cal = 6 kcal

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Q: How much heat is needed to raise temp of 80g of water from 15 degrees celsius to 90 degrees celsius?
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