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Is psi for water pressure?
It is mostly used when referring to air. I suppose it can be used but I would expect it to be inches cubed instead of per square inch when dealing with water.
A column of water 2.31 ft high exerts a pressure of 1 pound per square inch how much pressure does a column of water 47 ft high exert?
Given that this stands out a mile as almost certainly a school homework question, to answer directly would be to make me complicit in cheating. So I will tell you how to calculate it, which would appear to be the point of the question: 1) The relationship between depth and pressure of water is linear. 2) If water X ft deep exerts a pressure of P lb/in2, then water of Y ft deep will obviously exert a pressure of P(Y/X) lbs/in2 Given thats information you can now solve the original question.
How do i divide a 5.5 inch page into 3 equal columns what fraction do i use?
To divide a 5.5 inch page into 3 equal columns, you would need to divide the total width of 5.5 inches by 3. This would give you 1.83 inches per column. To represent this as a fraction, you would express it as 1 and 5/6 inches per column, which is the same as 11/6 inches per column.
If you have a 1000 gallon container of water that has a half inch pipe coming out the bottom of the container what is the psi at that pipe and does the height and circumference of the container matter?
Shape matters First, the shape of the vessel matters. The outward pressure applied to the inside of the walls of the vessel is not unifom, regardless of its shape, but it will be more uniform for cylindrical vessels and more uniform, still, for spherical ones. Second, be advised that the contributions below apply more to water columns than to vessels. The pressure is all dependant on the height of the column of water. Calculate the weight of a 1 ft by 1 ft column of water to the height of the column. It doesn't really matter if the column is ACTUALLY 1 ft by 1 ft, the physics works out that way. Simply said, if the height of the container is 10 ft, that would give you a 10 cubic ft column of water. Ten cubic ft of water would be about 74.8 gallons. A gallon weighs about 8 pounds, giving you a column of water that weighs about 598 pounds. That would make the pressure at the bottom of the tank 598 pounds per square foot. To convert that to inches, divide by the number of square inches in a square foot, which is 144, leaving you about 4.1 PSI, if the water column is 10 ft high. Pressure at the bottom of a water tank Since for practical purposes, water weights approximately 8.34 lb. per gallon, 1000 gallons of water would weight 8340 lb. The bottom of the container does matter, as the 8,340 lb. would be distributed evenly over the entire surface area of the bottom. The wider the tank, the lower the psi. Conversely, the narrower the tank, the higher the psi. The water will exert exactly the same pressure per square inch on a 1/2 inch pipe as on a 1 inch pipe or a 6 inch pipe. To calculate the pressure at the bottom of the tank, calculate the bottom surface as Pi times radius squared. Example: with a 3-ft diameter tank: 3.14159 X 2.25 = 7.06858 sq. ft. (Pi times the radius squared.) Therefore 8,340 lb. per 7.06858 sq ft = 8,340 lbs per 1017.87 sq in = 8.194 psi. Calculate pressure for other diameter tanks by simply substituting the diameter in the above example. The only factor that would effect the answer to your question would be the depth of the water. One foot of fresh water depth will exert .43 psi on a gauge. The size, shape and configuration of the container have no bearing on it. If you had a gauge at the bottom of a million gallon swimming pool that was 10 feet deep and you had a gauge at the bottom of a 4 inch pipe that was running vertical 10 feet deep (approximately 6.5 gallons) both gauges would read 4.3 psi.
How much pressure would be generated by raising water 1 degree?
The answer depends on the coefficient of thermal expansion of water, and the increase in pressure would be very small. In fact, between 0 and 4 deg C, water contracts and so the pressure will drop!
How does 4 ounce gas pressure convert to inches of water column?
To convert gas pressure from ounces to inches of water column, you can use the conversion factor of 1 ounce = 0.2773 inches of water column. Therefore, a gas pressure of 4 ounces would be equivalent to 4 * 0.2773 = 1.1092 inches of water column.
How do you convert inch of water column to volume?
To convert inches of water column to volume, you would need to know the area over which the water column is acting. Once you have the area, you can calculate the volume by multiplying the inches of water column by the area in square inches. The formula would be: Volume = Inches of water column * Area.
Why is the value of atmospheric pressure compared to mercury?
Mercury is used in barometers as it is a dense liquid that allows small changes in atmospheric pressure to be measured accurately. The height of the mercury column in the barometer is directly related to the atmospheric pressure. By comparing atmospheric pressure to the height of mercury in a barometer, the pressure can be quantified in units of millimeters or inches of mercury.
What is the pressure exerted at the base of a water riser by a column of water in a riser 95 feet high?
The pressure exerted at the base of a water riser by a column of water is determined by the height of the column above the base. In this case, with a column of water 95 feet high, the pressure at the base would be approximately 41.1 pounds per square inch. This calculation is done using the formula P = ρgh, where P is pressure, ρ is density of water, g is acceleration due to gravity, and h is the height of the column.
Where in the water column would you expect to find the the following conditions the highest pressure readings the densest waters or the warmest temperatures?
The highest pressure readings would be found at the bottom of the water column due to the weight of the overlying water. The densest waters would also be found at deeper levels where cold temperatures and high pressure compress seawater. The warmest temperatures are typically found near the surface of the water column where sunlight can penetrate and warm the water.
How many inches of water are in a gallon of water?
this question can't be answered because you can only get a surface area calculation from 30X42 inches, (which is 1260 square inches) To calculate the volume, you need the depth of the water as well.
How many psi equals 1 water column?
You need to know how high the water column is to calculate the pressure it exerts at its base! For example, a column of water 1 metre deep would exert a pressure of 9.81 kPa at its base (density x gravity x depth - 1000 * 9.81 * 1). This would be equal to approx 1.42 PSI.
How does the pressure at the bottom of a 76 cm column of mercury in a barometer compare with air pressure at the bottom of the atmosphere?
The pressure at the bottom of a 76 cm column of mercury in a barometer would be equal to the atmospheric pressure pushing down on the mercury column. This is because the height of the mercury column in a barometer is directly related to the atmospheric pressure. Thus, the pressure at the bottom of the mercury column would be the same as the air pressure at the bottom of the atmosphere.
How many psi is 1 inch water column?
Well that depends, first off pressure is equal to specific gravity times height. P=SG*h. so the pressure due to the water column would be 0.0361 psi given that SG of water = 62.4 lb/ft^3. Then you have to take into consideration any other pressures acting on the water. If the top of the column is open to the air then the absolute pressure would be 14.7321 psi given that atmospheric pressure is 14.696. The basic formula to make this calculation in any situation is P=P0+SG*h where P0 is the pressure above the column.
WC on gas line stand for?
"WC" on a gas line typically stands for "water column," which is a unit of measurement used to express pressure in a gas system. It represents the height of a column of water that would exert the same pressure as the gas being measured.
Where in the water column would you expect to find the following conditions the highest pressure readings the densest waters the warmest temperatures?
Highest pressure readings would be found at the bottom of the water column. The densest waters are typically found at the bottom as well, due to the weight of the overlying water. The warmest temperatures are usually found near the surface where sunlight can penetrate and heat the water.
How would one calculate the forces exerted by a given volume of water upon the faces of a rectangular box which it fills?
The pressure of the water varies as a function of depth. To calculate the pressure at a given depth take a column of water terminating in some area at the depth you want. For instance, take a 1 in^2 area that is 30 ft deep. The volume of water in this column is 360 cubic inches. Multiply this by the density of water to get the weight of the water in this column. That weight (the force due to gravity) divided by the area (taken to be 1 square inch) is equal to the pressure. Now that we can calculate the pressure as a function of depth, we can then find the pressure for a small horizontal band on the wall with an area equal to the a small increment of height times the width of the wall. This multiplied by the pressure gives the force on that small band. Sum up all the bands (or, really, integrate over the vertical axis) with the pressure calculated at each depth as outlined above.
