.4 psi
The pressure exerted by a water tank is determined by the height of the water column above the point in question. The pressure increases by approximately 9.81 kPa (kilopascals) for every meter of water height due to gravity. Therefore, for every meter of water, you would experience about 9.81 kPa of pressure, regardless of the total volume of the tank.
It is mostly used when referring to air. I suppose it can be used but I would expect it to be inches cubed instead of per square inch when dealing with water.
Given that this stands out a mile as almost certainly a school homework question, to answer directly would be to make me complicit in cheating. So I will tell you how to calculate it, which would appear to be the point of the question: 1) The relationship between depth and pressure of water is linear. 2) If water X ft deep exerts a pressure of P lb/in2, then water of Y ft deep will obviously exert a pressure of P(Y/X) lbs/in2 Given thats information you can now solve the original question.
To divide a 5.5 inch page into 3 equal columns, you would need to divide the total width of 5.5 inches by 3. This would give you 1.83 inches per column. To represent this as a fraction, you would express it as 1 and 5/6 inches per column, which is the same as 11/6 inches per column.
A decrease in the height of the mercury column in a barometer indicates a drop in atmospheric pressure. This can occur due to changes in weather systems, such as the approach of a low-pressure system, which is often associated with cloudy or rainy conditions. Conversely, an increase in the column height would indicate rising atmospheric pressure.
To convert gas pressure from ounces to inches of water column, you can use the conversion factor of 1 ounce = 0.2773 inches of water column. Therefore, a gas pressure of 4 ounces would be equivalent to 4 * 0.2773 = 1.1092 inches of water column.
To convert inches of water column to volume, you would need to know the area over which the water column is acting. Once you have the area, you can calculate the volume by multiplying the inches of water column by the area in square inches. The formula would be: Volume = Inches of water column * Area.
The common method to measure atmospheric pressure employs an inverted column submerged in a fluid to determine the level at which the column has to be raised to equalize the external atmospheric pressure and the internal column pressure. The height at which the fluid inside the column ceases to increase is correlated to atmospheric pressure. Due to mercury's high density, this level is on the order of inches (~30 inches of mercury at atmospheric pressure). If water were to be used the column would have to be ~32 feet tall in order to develop the equalized pressures between the column and atmosphere.
The pressure exerted at the base of a water riser by a column of water is determined by the height of the column above the base. In this case, with a column of water 95 feet high, the pressure at the base would be approximately 41.1 pounds per square inch. This calculation is done using the formula P = ρgh, where P is pressure, ρ is density of water, g is acceleration due to gravity, and h is the height of the column.
The highest pressure readings would be found at the bottom of the water column due to the weight of the overlying water. The densest waters would also be found at deeper levels where cold temperatures and high pressure compress seawater. The warmest temperatures are typically found near the surface of the water column where sunlight can penetrate and warm the water.
this question can't be answered because you can only get a surface area calculation from 30X42 inches, (which is 1260 square inches) To calculate the volume, you need the depth of the water as well.
You need to know how high the water column is to calculate the pressure it exerts at its base! For example, a column of water 1 metre deep would exert a pressure of 9.81 kPa at its base (density x gravity x depth - 1000 * 9.81 * 1). This would be equal to approx 1.42 PSI.
The pressure at the bottom of a 76 cm column of mercury in a barometer would be equal to the atmospheric pressure pushing down on the mercury column. This is because the height of the mercury column in a barometer is directly related to the atmospheric pressure. Thus, the pressure at the bottom of the mercury column would be the same as the air pressure at the bottom of the atmosphere.
Well that depends, first off pressure is equal to specific gravity times height. P=SG*h. so the pressure due to the water column would be 0.0361 psi given that SG of water = 62.4 lb/ft^3. Then you have to take into consideration any other pressures acting on the water. If the top of the column is open to the air then the absolute pressure would be 14.7321 psi given that atmospheric pressure is 14.696. The basic formula to make this calculation in any situation is P=P0+SG*h where P0 is the pressure above the column.
"WC" on a gas line typically stands for "water column," which is a unit of measurement used to express pressure in a gas system. It represents the height of a column of water that would exert the same pressure as the gas being measured.
Highest pressure readings would be found at the bottom of the water column. The densest waters are typically found at the bottom as well, due to the weight of the overlying water. The warmest temperatures are usually found near the surface where sunlight can penetrate and heat the water.
To raise water 1 meter, you would need to exert a pressure equivalent to the weight of the water column above. For water, the pressure increase with depth is 9.81 kPa per meter. Therefore, to raise water 1 meter, you would need to apply a pressure of 9.81 kPa.