Dcroucher
DEPENDS HOW MUCH MOTHER LIQUID YOU START WITH. EXAMPLE,
100 MLS WITH 35 GRMS OF ADDITIVE (subtract the volume of displacement)
would be a 35 % dilution. In theory you would add 15% if mother liquid was 100 Mil's, (minus its displacement,) this is what a volumetric flask is for,,,
hope this helped.. if Ir's not to important just figure your total liquid and add 15% of your whatever
Wiki User
∙ 14y agoadd 4 parts water per part solution
Let's assume you have 1 L of the 37% solution by volume of chemical A. So your solution would contain 0.37 L of A & 0.63 L of water.0.37 L of A / (0.37 L of A + 0.63 L of water) = 37% solution of AObviously in order to dilute the solution to 2% we have to add water. Now we need to figure out how much. We'll call it X. So you set up the ratio as follows & solve for X.0.37 / (0.37 + 0.36 + X ) = 0.020.37 = 0.02 (1.00 + X)0.37 = 0.02 + 0.02X0.37 - 0.02 = 0.02 + 0.02X - 0.020.35 = 0.02X0.35/0.02 = XX = 17.5, so you would have to add 17.5 L of water to the originial 37% solution to dilute it to 2%.Obviously this answer will change depending on how much of the 37% solution you have to start with but the procedure to figure it out is still the same.
96
98 mL
75 litres
well in dilute acid there is 1-10 percent and there will be only 90 percent of water so i was told from a science teacher who studied this
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
Yes, maple sap is a dilute solution as it is mainly composed of water with small amounts of sugars, minerals, and other organic compounds extracted from the tree.
To dilute the copper chlorine solution from 100,000 ppm to 1 ppm, you would need to dilute it by a factor of 100,000. This means you would need 100,000 liters of water to dilute 1 liter of the original solution.
You would need 999,999L of water to dilute used copper chloride solution
The amount of water in a dilute acid will depend on the concentration of the acid. A dilute acid contains more water than acid molecules, usually more water than acid. The exact ratio of water to acid molecules will depend on the specific concentration of the acid.
To make a 1% HCl solution from a 35% HCl solution, you would need to dilute the concentrated solution with water. The ratio of concentrated HCl to water would be approximately 1:34. So, to make 1% HCl, you would mix 1 part of the 35% HCl solution with 34 parts of water.
add 4 parts water per part solution
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
To make a 20% dextrose solution, you need to dilute the 70% dextrose solution with water. You need to use 178.57 ml of the 70% dextrose and 321.43 ml of water to make 500 ml of 20% dextrose solution.
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
Nitric acid can be dilute or concentrated. This is simply a matter of how much of it you have in a given amount of a solution, which is variable.