30 J
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
Her average speed was 10 m/s. You probably missed something in the question, there isn't enough there to determine "how much it increased by".
The work done to increase the speed of an object is equal to the change in its kinetic energy. The change in kinetic energy can be calculated using the formula ΔKE = 0.5 * m * (vf^2 - vi^2), where m is the mass of the object, vf is the final velocity, and vi is the initial velocity. Substituting the given values, the work done on a 1000-kg car to increase its speed from 1 m/s to 2 m/s would be ΔKE = 0.5 * 1000 * (2^2 - 1^2) = 1000 J.
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
the increase from 7000 to 8000 is 1000
3000j
312.5 J
30 J
375 Js (((((((((((: this is the right answer
3000 J *Shelby Sarah*
750 j
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
Yes, but if you increase the speed of your breathing too much you can hyperventilate and / or pass out.
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.