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How much work must be done on 1000 kg car to increase its speed from 1 ms to 2 mg?
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How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
30 J
How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work must be done on a 24 kg shopping cart to increase its speed from 1 ms to 4ms?
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
She ran 300 meters in 30 seconds how much did her speed increase?
Her average speed was 10 m/s. You probably missed something in the question, there isn't enough there to determine "how much it increased by".
How much work must be done on a 1000-kg car to increase its speed from 1 ms to 2 ms?
The work done to increase the speed of an object is equal to the change in its kinetic energy. The change in kinetic energy can be calculated using the formula ΔKE = 0.5 * m * (vf^2 - vi^2), where m is the mass of the object, vf is the final velocity, and vi is the initial velocity. Substituting the given values, the work done on a 1000-kg car to increase its speed from 1 m/s to 2 m/s would be ΔKE = 0.5 * 1000 * (2^2 - 1^2) = 1000 J.
How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
How much is the increase from 7000 to 8000?
the increase from 7000 to 8000 is 1000
How much work is done to increase a 20 kg scooters speed from 10 ms to 20 ms?
3000j
How much work must be done on a 5-kg sled to increase its speed from 10 m/s to 15 m/s?
312.5 J
How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
30 J
How much work is done to increase a 20-kg scooter's speed from 10 m/s to 20 m/s?
3000 J *Shelby Sarah*
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
750 j
How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work is done to increase a 20 kg scooter's speed from 10 ms to 20 ms?
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
How much work is done to increase a 20 kg scooter speed from Ms to 20 ms?
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
