Wiki User
∙ 9y agoKinetic energy = 1/2 M V2
At the lower speed, the car's KE is (500) (1)2 = 500 joules
At the higher speed, the car's KE is (500) (2)2 = 2,000 joules
The difference is the energy i.e. the work you have to put into it
to raise the speed from 1 m/s to 2 m/s.
(2,000 - 500) = 1,500 joules
Wiki User
∙ 9y ago30 J
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
Her average speed was 10 m/s. You probably missed something in the question, there isn't enough there to determine "how much it increased by".
To increase the speed of the car from 1 m/s to 2 m/s, you must apply a force using Newton's second law: Force = mass x acceleration. The force required will depend on the time over which you wish to achieve this acceleration, as accelerating too quickly may require a larger force.
The work done to increase the speed of an object is equal to the change in its kinetic energy. The change in kinetic energy can be calculated using the formula ΔKE = 0.5 * m * (vf^2 - vi^2), where m is the mass of the object, vf is the final velocity, and vi is the initial velocity. Substituting the given values, the work done on a 1000-kg car to increase its speed from 1 m/s to 2 m/s would be ΔKE = 0.5 * 1000 * (2^2 - 1^2) = 1000 J.
3000j
312.5 J
30 J
3000 J *Shelby Sarah*
750 j
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
Yes, but if you increase the speed of your breathing too much you can hyperventilate and / or pass out.
225000 J