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Kinetic energy = 1/2 M V2

At 2 m/s, the board's KE is [ (1/2) (5) (2)2 ] = 10 joules.

At 10 m/s, the board's KE is [ (1/2) (5) (10)2 ] = 250 joules.

The difference is 240 joules, which is the work you have to put into it

to give it the additional kinetic energy.

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Q: How much work must be done on a 5 kg skateboard to increase its speed from 2 m per s to 10 m per s?
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