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It need not necessarily do so. For example, consider f(x) = 1/(x-2)Suppose you start with x = 5 which gives f(x) = 0.33... and x = -5 which gives f(x) = -0.14286

Bisecting the interval (-5, 5) gives x = 0 and so f(x) = -0.5

which is further away from the previous value.


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7y ago
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1y ago

In the bisection method, the root convergence occurs by repeatedly dividing the interval that contains the root into smaller intervals. In each iteration, the method checks whether the midpoint of the interval is the root or if it lies on one side of the root. The method then selects the subinterval where the root lies and continues to divide it further until the desired level of accuracy is achieved. The convergence is guaranteed because the interval containing the root is halved in each iteration.

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Q: How root converges in bisection method?
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What is the Real root of 1-0.6x divided by x using bisection method?

The root of f(x)=(1-0.6x)/x is 1.6666... To see how the bisection method is used please see the related question below (link).


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If this is in the context of finding a root of an equation, the answer is to make some guesses. Find value x1 and x2 such that f(x1) and f(x2) have opposite signs. Then, provided that f is a continuous function over (x1, x2), the bisection method will find its root.


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The main disadvantage of the bisection method for finding the root of an equation is that, compared to methods like the Newton-Raphson method and the Secant method, it requires a lot of work and a lot of iterations to get an answer with very small error, whilst a quarter of the same amount of work on the N-R method would give an answer with an error just as small.In other words compared to other methods, the bisection method takes a long time to get to a decent answer and this is it's biggest disadvantage.


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