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I would answer no because 3√2 ____ 5√2 Would simplify to 3 divided by 5 and that is not irrational.
phi = [1+sqrt(5)]/2 sqrt(5) is irrational and so phi is irrational.
5 squared is 5*5 is 25. 25 is not an irrational number.
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
Yes, √3 + √5 is irrational.
no. an example of an irrational number would be like the square root of 3
I would answer no because 3√2 ____ 5√2 Would simplify to 3 divided by 5 and that is not irrational.
5 isn't a irrational number.
5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!
phi = [1+sqrt(5)]/2 sqrt(5) is irrational and so phi is irrational.
No. If a number is irrational, it continues endlessly without a pattern. Since 2.5 stops at 5, it is rational; but if it were, say, 2.573583..., it would be irrational. Also, it can be written as the fraction 25/10, or 5/2.
5 squared is 5*5 is 25. 25 is not an irrational number.
Yes, the sqrt of (3+5) is irrational, because: sqrt(3+5) = sqrt of 8, which is irrational
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
7 plus the square root of 5 is an irrational number because the square root of 5 is a never ending decimal number that can't be expressed as a fraction.
Yes, √3 + √5 is irrational.
No