7 plus the square root of 5 is an irrational number because the square root of 5 is a never ending decimal number that can't be expressed as a fraction.
sqrt(27)
4.01234567891011121314... keep appending the next counting number on the end {15, 16, 17, 18, 19, 20, ...} and you will have an irrational number between 4 and 5.
No. If a number is irrational, it continues endlessly without a pattern. Since 2.5 stops at 5, it is rational; but if it were, say, 2.573583..., it would be irrational. Also, it can be written as the fraction 25/10, or 5/2.
At least one of the factors has to be irrational.* An irrational number times ANY number (except zero) is irrational. * The product of two irrational numbers can be either rational or irrational.
5 squared is 5*5 is 25. 25 is not an irrational number.
√ 5 is an irrational number. Any square root of a prime number is irrational.
5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!
No it is not.
The product will be irrational.
No, -5 is not an irrational number. Irrational numbers are numbers that cannot be represented as the quotient of two integers. Since -5 is already an integer, it is rational.
Irrational.
5.4 = 5 2/5 = 27/5 so it is a rational number.
No. 5 is not an irrational number. 5 is an integer (whole number) and all integers are rational - that is, they can be expressed as a ratio. In this case, 5/1.
phi = [1+sqrt(5)]/2 sqrt(5) is irrational and so phi is irrational.
no. an example of an irrational number would be like the square root of 3
5 = 5.0005, therefore, is not irrational as it does not contain a perpetual non-repeating character string after the decimal.However, 5 is a prime number.