A graph is represents a function if for every value x, there is at most one value of y = f(x).
The graph of a continuous function will not have any 'breaks' or 'gaps' in it. You can draw it without lifting your pencil or pen. The graph of a discrete function will just be a set of lines.
For a 2-dimensional graph if there is any value of x for which there are more than one values of the graph, then it is not a function. Equivalently, any vertical line can intersect the a function at most once.
The "vertical line test" will tell you if it is a function or not. The graph is not a function if it is possible to draw a vertical line through two points.
A linear function would be represented by a straight line graph, so if it's not a straight line, it's nonlinear
Because f represents a function.
A graph represents a function if and only if every input generates a single output.
If the graph is a function, no line perpendicular to the X-axis can intersect the graph at more than one point.
If the function is a straight line equation that passes through the graph once, then that's a function, anything on a graph is a relation!
sine graph will be formed at origine of graph and cosine graph is find on y-axise
This graph fails the vertical line test at x = 3This graph is not the graph of a function.
A graph is represents a function if for every value x, there is at most one value of y = f(x).
Test it by the vertical line test. That is, if a vertical line passes through the two points of the graph, this graph is not the graph of a function.
an exponential function flipped over the line y=x
The vertical line test! Imagine a vertical line going through all points of the graph. As long as the vertical line only touches the graphed line once, it's a function. If it touches more than once, it is not.
The graph of a continuous function will not have any 'breaks' or 'gaps' in it. You can draw it without lifting your pencil or pen. The graph of a discrete function will just be a set of lines.
Does the graph above show a relation, a function, both a relation and a function, or neither a relation nor a function?