You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(x + 5)(2x - 3)
(2x + 1)(x + 2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
The answer is (2x^2+3)(4x+1)
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(x + 5)(2x - 3)
(2x+3)(2x+4)
(x + 1)(2x + 5)
(2x + 1)(x + 2)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(2x+3)(x+3)
(2x - 3)(2x - 3)
(2x - 5)(2x - 5) or (2x - 5) squared
2x(x^2+x-6)
The answer is (2x^2+3)(4x+1)
x(x + 2)