(x + 5)(2x - 3)
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(x + 5)(x + 2)
(a + x^2)(b + y^2)
6xyz(3x + 2y + z)
4(x+y)^2
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
(x + 5)(x + 2)
this problem cannot be factored
(a + x^2)(b + y^2)
(6x + 1)(x + 13)
(x + 2)(x + 3)
No
6xyz(3x + 2y + z)
(a + 2 - b) (a + 2 + b)
4(x+y)^2
(3q + 2p)(9q + 7p)
(6x + t)(3x + t)