(n + 8)(n - 8)
100*n/64100*n/64100*n/64100*n/64
Suppose you have a number N and you want to find its largest prime factor. It is probably easiest to start at the bottom.Find the smallest prime factor, p.Find its factor pair = N/p.If the second number (= N/p) is a prime, then it is the largest prime factor.if not, replace N by N/p and go back to the top.
The power of a product states that when you raise a product of factors to a power, you can distribute the exponent to each factor. Mathematically, this is expressed as ((ab)^n = a^n \times b^n). If you have the same factor, such as (a), the expression ((a^m)^n) simplifies to (a^{m \cdot n}). For example, if (a = 2), (m = 3), and (n = 2), then ((2^3)^2 = 2^{3 \cdot 2} = 2^6 = 64).
A 64-output line decoder has 6 data inputs. This is because a decoder's number of outputs (N) is related to the number of inputs (n) by the formula ( N = 2^n ). Therefore, to achieve 64 outputs, you need ( n ) such that ( 2^n = 64 ), which means ( n = 6 ).
Did you mean find n where (2^5)^n = 64? (Sorry - the superscript symbol won't work!) I think that would need logarithms to calculate, because 2^5 = 32. Or did you mean find the power of 2 that = 64?
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
n
100*n/64100*n/64100*n/64100*n/64
The common factor would be n.
The constant factor that each value in an exponential decay pattern is multiplied by the next value. The decay factor is the base in an exponential decay equation. for example, in the equation A= 64(0.5^n), where A is he area of a ballot and the n is the number of cuts, the decay factor is 0.5.
1n=n 1xn if n mean 64, n=64, 1xn=64,1n=64
When the first number can divide the second without remainder. The formal definition would be as follows: For integers x and y, x is a factor of y if there exists an integer n such that y = n*x
40n^2 + 64n = n(40n + 64) = 8n(5n + 8)
64
Suppose you have a number N and you want to find its largest prime factor. It is probably easiest to start at the bottom.Find the smallest prime factor, p.Find its factor pair = N/p.If the second number (= N/p) is a prime, then it is the largest prime factor.if not, replace N by N/p and go back to the top.
The power of a product states that when you raise a product of factors to a power, you can distribute the exponent to each factor. Mathematically, this is expressed as ((ab)^n = a^n \times b^n). If you have the same factor, such as (a), the expression ((a^m)^n) simplifies to (a^{m \cdot n}). For example, if (a = 2), (m = 3), and (n = 2), then ((2^3)^2 = 2^{3 \cdot 2} = 2^6 = 64).
If you mean: n/5 = 64/40 then the value of n is 8