To graph the inequality ( x < 3 ), you would start by drawing a vertical dashed line at ( x = 3 ). The dashed line indicates that points on the line are not included in the solution. Next, shade the region to the left of the line, which represents all values of ( x ) that are less than 3. This shaded area shows the solution set for the inequality.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To graph the solution to the inequality (-3x - 720 < 0), you first need to solve for (x). Rearranging the inequality gives (x > -240). On the graph, this means you would draw a number line, shade to the right of (-240), and place an open circle at (-240) to indicate that (-240) is not included in the solution.
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To graph this in Cartesian coordinates start by solving the inequality for either x or y: y --less than or equal to-- 3-x/3 Now, if this were not an equality we would have y=3-x/3 this equation would yield a linear graph with a slope of -1/3 and a y intercept of 3 But the graph for the inequality must also could include all of the points (x,y) below this line so we end up with not a line but an entire region. so right now in your head picture the line y=3-x/3. now color in the region below the line. this is the region where y is less than 3- x/3 and the line its self accounts for y=3-x/3.
To graph the solution to the inequality (-3x - 720 < 0), you first need to solve for (x). Rearranging the inequality gives (x > -240). On the graph, this means you would draw a number line, shade to the right of (-240), and place an open circle at (-240) to indicate that (-240) is not included in the solution.
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
If the graph shows no solutions, it typically indicates that the inequality is contradictory or that there are no values that satisfy the condition. This could represent an inequality such as ( x < x ) or ( x > x ), which is impossible. Therefore, the solution set is empty, often denoted as ( \varnothing ) or ( { } ).
x - 3 is not an inequality.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3