Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
if this is an x,y plot, it would be a vertical line at x = -3
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To graph this in Cartesian coordinates start by solving the inequality for either x or y: y --less than or equal to-- 3-x/3 Now, if this were not an equality we would have y=3-x/3 this equation would yield a linear graph with a slope of -1/3 and a y intercept of 3 But the graph for the inequality must also could include all of the points (x,y) below this line so we end up with not a line but an entire region. so right now in your head picture the line y=3-x/3. now color in the region below the line. this is the region where y is less than 3- x/3 and the line its self accounts for y=3-x/3.
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
x - 3 is not an inequality.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
if this is an x,y plot, it would be a vertical line at x = -3
Neither x-1 nor x4 is an equation or an inequality. There is, therefore, nothing to graph anything.
Get the variables on one side of the inequality sign, and the numbers on the other side. You do this by using inverse operations. Divide the number by the variable. If you divide using a negative number you flip the inequality sign. An example of what you are looking at should look like x > 3. You would graph this example by drawing a number line, then putting an open cirlce at three, and shading the number line on the right side of the three. This shows that x is greater than three.