Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
if this is an x,y plot, it would be a vertical line at x = -3
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
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"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
To graph this in Cartesian coordinates start by solving the inequality for either x or y: y --less than or equal to-- 3-x/3 Now, if this were not an equality we would have y=3-x/3 this equation would yield a linear graph with a slope of -1/3 and a y intercept of 3 But the graph for the inequality must also could include all of the points (x,y) below this line so we end up with not a line but an entire region. so right now in your head picture the line y=3-x/3. now color in the region below the line. this is the region where y is less than 3- x/3 and the line its self accounts for y=3-x/3.
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
x - 3 is not an inequality.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
if this is an x,y plot, it would be a vertical line at x = -3
Neither x-1 nor x4 is an equation or an inequality. There is, therefore, nothing to graph anything.