By using the quadratic equation formula: x = -5 and x = 3
You would have to take the cube root of 400000, which equals 73.68
You'd need another equation to sub in
To start, try breaking down sin3x using a double angle formula. Message me if you need more help!
75
Say you have a pair of equations like a+b=1 and 2a+3b=5. To solve using substitution you would set one equation against one variable (say a=1-b) then plug that into the other (2(1-b)+3b=5), then solve for the one variable you have there and then plug that result into the other equation (in this case b=3 and a=-2).
By using the quadratic equation formula: x = -5 and x = 3
You would have to take the cube root of 400000, which equals 73.68
You'd need another equation to sub in
To start, try breaking down sin3x using a double angle formula. Message me if you need more help!
75
You would take 2 and replace it for x in your other equation and solve.
28
You would do it it by oppisites. 3+2+4=9 which equals C.
6x+7y=-6 3(-2x-3y=2) +________ -2y=0 => y=0 Therefore x=-1
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.