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The perimeter is: 1+10+1+10 = 22 cm
2 x (24 + 10)...68cm
Perimeter (p) = 2*l+2*w = 2*10 + 2*5 = 20+10 = 30 cm
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
Assuming the object is a rectangle, the perimeter is (2 x 7cm) + (2 x 10 cm) = 34cm
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the length is 15 centimeters and the width is 10 centimeters. To find the perimeter, you would add up all four sides: 15 cm + 10 cm + 15 cm + 10 cm = 50 cm. Therefore, the perimeter of the rectangle is 50 centimeters.
Draw it with dimensions of (6 cm) by (3 cm).
The perimeter is: 1+10+1+10 = 22 cm
40 cm Perimeter = 2 L + 2W = 30 + 10
10*2+5*2 = 30 CM
2 x (24 + 10)...68cm
Perimeter (p) = 2*l+2*w = 2*10 + 2*5 = 20+10 = 30 cm
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
Assuming the object is a rectangle, the perimeter is (2 x 7cm) + (2 x 10 cm) = 34cm
Yes.Yes.Yes.Yes.