The perimeter is: 1+10+1+10 = 22 cm
2 x (24 + 10)...68cm
Perimeter (p) = 2*l+2*w = 2*10 + 2*5 = 20+10 = 30 cm
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
Assuming the object is a rectangle, the perimeter is (2 x 7cm) + (2 x 10 cm) = 34cm
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
Draw it with dimensions of (6 cm) by (3 cm).
The perimeter of a rectangle is P = 2(l + w) where: l = length w = width Let: l = 15 cm w = 10 cm Then: P = 2(15 cm + 10 cm) = 2(25 cm) = 50 cm So the perimeter of a rectangle is 50 cm.
The perimeter is: 1+10+1+10 = 22 cm
40 cm Perimeter = 2 L + 2W = 30 + 10
10*2+5*2 = 30 CM
There are a lot of different shapes with a perimeter of 22 cm, all with different areas. For example, a rectangle of 1 cm by 10 cm has an area of 10 sq. cm; a rectangle of 2 cm by 9 cm has an area of 18 sq. cm. Both have a perimeter of 22 cm. It depends on the shape.
2 x (24 + 10)...68cm
Perimeter (p) = 2*l+2*w = 2*10 + 2*5 = 20+10 = 30 cm
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
Assuming the object is a rectangle, the perimeter is (2 x 7cm) + (2 x 10 cm) = 34cm