To make y a function x, simply get the y to equal the rest of the values. eg. y=3x+1
To solve for the inverse of an equation, first, replace the function notation (e.g., (y = f(x))) with (y). Then, swap the roles of (x) and (y) in the equation. After that, solve for (y) in terms of (x). Finally, replace (y) with (f^{-1}(x)) to express the inverse function.
Well, if you solve the equation for "y", you have "y" as a function of "x". Or you can do it the other way round; solve for "x", to get "x" as a function of "y" (the first option is more commonly used, though).
Let's assume (for simplicity) that "y" is a function of "x". That means that for every value of "x", there is a unique value of "y". In this case, if the equation can be solved for "y", it is a function. Some equations are difficult or impossible to solve explicitly for "y"; in this case, "y" may still be a function of "x", if for every value of "x" only a single value of "y" is possible for the equation. However, if this is the case, it may be difficult to verify.
Solve for what? Do you want to rearrange the equation for y to be a function of x? y = 70 - 4x Do you want to rearrange it as a function of y? x = (70 - y) / 4 You'll need to be more specific in exactly what you want done.
Set x = 0 and solve the resulting equation in y for the y-intercept. Set y = 0 and solve the resulting equation in x for the x-intercept.
To solve for the inverse of an equation, first, replace the function notation (e.g., (y = f(x))) with (y). Then, swap the roles of (x) and (y) in the equation. After that, solve for (y) in terms of (x). Finally, replace (y) with (f^{-1}(x)) to express the inverse function.
In its normal form, you do not solve differential equation for x, but for a function of x, usually denoted by y = f(x).
Well, if you solve the equation for "y", you have "y" as a function of "x". Or you can do it the other way round; solve for "x", to get "x" as a function of "y" (the first option is more commonly used, though).
If it is a linear function, it is quite easy to solve the equation explicitly, using standard methods of equation-solving. For example, if you have "y" as a function of "x", you would have to solve the variable for "x".
Let's assume (for simplicity) that "y" is a function of "x". That means that for every value of "x", there is a unique value of "y". In this case, if the equation can be solved for "y", it is a function. Some equations are difficult or impossible to solve explicitly for "y"; in this case, "y" may still be a function of "x", if for every value of "x" only a single value of "y" is possible for the equation. However, if this is the case, it may be difficult to verify.
Solve for what? Do you want to rearrange the equation for y to be a function of x? y = 70 - 4x Do you want to rearrange it as a function of y? x = (70 - y) / 4 You'll need to be more specific in exactly what you want done.
Set x = 0 and solve the resulting equation in y for the y-intercept. Set y = 0 and solve the resulting equation in x for the x-intercept.
To find the inverse of a function algebraically, start by replacing the function notation ( f(x) ) with ( y ). Then, interchange the roles of ( x ) and ( y ) in the equation, which means you solve for ( y ) in terms of ( x ). Finally, express the new equation as ( f^{-1}(x) = y ). Verify that the composition of the function and its inverse yields the identity function, confirming they are true inverses.
The y-intercept of a function is the point at which the graph intersects the y-axis, meaning it is the value of y when x is equal to zero. To solve for the y-intercept in an equation, substitute 0 for x and simplify the equation to find the corresponding y value. For example, in the equation (y = 2x + 3), substituting 0 for x gives (y = 3), so the y-intercept is at the point (0, 3).
To determine if the equation ( x^2 + y^2 = 1 ) can be expressed as ( y ) as a function of ( x ), you can solve for ( y ). Rearranging gives ( y^2 = 1 - x^2 ), leading to ( y = \pm \sqrt{1 - x^2} ). Since there are two values of ( y ) (one positive and one negative) for most values of ( x ) in the interval ([-1, 1]), ( y ) cannot be expressed as a single-valued function of ( x ). Thus, the equation does not define ( y ) as a function of ( x ).
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
you have to solve y to get the answer