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To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
The given expression is not an equation because it has no equality sign but for a line to be parallel to another line they both will have the same slope but with different y intercepts
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.
To find the equation of a line parallel to ( y = 3x + 5 ), we need to use the same slope, which is 3. Using the point-slope form, we can write the equation as ( y - 3 = 3(x + 2) ). Simplifying this gives ( y = 3x + 9 ). Thus, the equation of the line in slope-intercept form is ( y = 3x + 9 ).
If you mean: 3x+2y = 5 then y = -3/2x+5/2 or y = -1.5x+2.5 Parallel equation: y = -1.5x+4
The parallel equation will have the same slope but with a different y intercept
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
i dont knows
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
A walking path across a park is represented by the equation y = –4x + 10. A new path will be built perpendicular to this path. The paths will intersect at the point (4, –6). Identify the equation that represents the new path.
The equation in slope-intercept form would be y=-2x
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25
The equation is x = -7.
For a straight line equation to be parallel to another straight line equation they both must have the same slopes but different y intercepts.
To find the slope-intercept form of the equation of a line that goes through the point (2, 2) and is parallel to the line ( y = x + 7 ), we first identify the slope of the given line, which is 1. Since parallel lines have the same slope, the new line will also have a slope of 1. Using the point-slope form ( y - y_1 = m(x - x_1) ) with ( m = 1 ) and the point (2, 2), we can rewrite it as ( y - 2 = 1(x - 2) ), which simplifies to ( y = x ).
The given expression is not an equation because it has no equality sign but for a line to be parallel to another line they both will have the same slope but with different y intercepts
The slope intercept form through 23 and 15 would be 5. This is considered as a math equation.