16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
= 53 9x3 + 9x2 + 5x1+ 3x1 27 + 18 + 5 + 3
The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus: the discriminant of -9x2 + 6x + 14 is 62 - 4 x -9 x 14 = 540
33
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
= 53 9x3 + 9x2 + 5x1+ 3x1 27 + 18 + 5 + 3
48
The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus: the discriminant of -9x2 + 6x + 14 is 62 - 4 x -9 x 14 = 540
33
9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2
9x2
9x2 + 9x - 10 =(3x - 2)(3x + 5)
(9x2 + 7)(9x2 - 7) = 81x4 - 49
9x2+2x-7 = (9x-7)(x+1) when factored
(-3x - 1)(3x - 7)