Then the radius bisects the chord.
yes
The longest chord of a circle is its diameter
the diameter
Perpendicular bisector.
Bisects
Perpendicular.
Bisects that chord
Then the radius bisects the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
YesAt a right angle
true, because both distances of the chord are congruent
yes
Yes, any diameter which is perpendicular to a chord bisects said chord. This can be proved most easily with a picture, but is proved using a congruent triangle proof. Both triangles include the points at the center of the circle and the intersection of the diameter and chord. The other points should be the endpoints of the chord. They are congruent by hypotenuse leg; it was given that they are right triangle by the "perpendicular", the "leg" is the segment between the center of the circle and the intersection, and it is equal in both triangles because it is the same segment in both triangles. The hypotenuses are equal because both are radii of the circle. Because the triangles are congruent, their sides must be so the two halves of the chord are congruent, and therefore the chord is bisected by the diameter.
False
I get 9
because the chord can be determine by the diameter and the diameter can be determine by the chord.