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A radius of a circle is perpendicular to a chord if and only if?

Bisects that chord


True or False If a radius of a circle intersects a chord it is perpendicular to that chord?

its false


Given radius and chord length. What is the height of arc to midpoint of chord?

Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).


A chord of a circle has length 4.2 cm and is 8 cm from the center of the circle what is the radius of the circle?

To find the radius of the circle, we can use the Pythagorean theorem. The chord divides the circle into two equal parts, each forming a right triangle with the radius. The radius, the distance from the center to the chord, and half the length of the chord form a right triangle. Using the Pythagorean theorem, we have (radius)^2 = (distance from center)^2 + (1/2 * chord length)^2. Substituting in the given values, we get (radius)^2 = 8^2 - (1/2 * 4.2)^2. Solving for the radius gives us a radius of approximately 7.48 cm.


What is the radius of a circle in which the longest chord has length y?

longest chord = diameter y = longest chord y = diameter radius = 1/2 diameter therefore, radius = 1/2y