What is the answers to -7 ( a + b - 5 ) + 8 ( -3a +2b ) + b ( 7 + 3 )
There is not enough information. Since 7 - 6 = 1 and 7 + 6 = 13, all that can be said is that the base b must satisfy 1 < b < 13.
b=5cm/h=6cm
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
b + b + b + 7 = 223b + 7 = 223b = 15b = 5
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
It might be pythagoras therom but it can only be Pythagoras when the traingle has a right angle. If it does then try to work it out using phythagoras. If the angle between the given sides is B, then: b2 = a2 + c2 - 2ac cos B ⇒ b2 = (7 cm)2 + (13 cm)2 - 2 x 7 cm x 13 cm x cos B ⇒ b = √(218 - 182 cos B) cm If it is a right angle triangle, with B the right angle, cos B = cos 90o = 0 and this becomes Pythagoras making the side: b = √218 cm ≈ 14.76 cm If there is a right angle, not between the 7 cm and 13 cm, then the 13cm side is the hypotenuse (as the hypotenuse must be the longest side) and the other side is: b = √(132 - 72) cm = √120 cm ≈ 10.95 cm
What is the answers to -7 ( a + b - 5 ) + 8 ( -3a +2b ) + b ( 7 + 3 )
There is not enough information. Since 7 - 6 = 1 and 7 + 6 = 13, all that can be said is that the base b must satisfy 1 < b < 13.
To find the density of object B, calculate its volume first: 10 cm (length) * 5 cm (width) * 2 cm (height) = 100 cm^3. Then, divide the mass by the volume: 300g / 100 cm^3 = 3 g/cm^3. The density of object B is 3 g/cm^3.
b=5cm/h=6cm
10 cm
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
area of rectangle = l* b = 5 * 2=10 cm^ 2
What is the correct answer?
Any number greater than or equal to 4*sqrt(45) cm or 26.83 cm (approx). To see that, suppose L ≥ sqrt(45) cm be the length of the rectangle and let B = 45/L cm Then Area = L*B = L*(45/L) = 45 cm2 If L = 9cm, then B = 45/9 = 5 cm and then perimeter = 2*(L+B) = 28 cm If L = 90 cm, then B = 0.5 cm and P = 181 cm If L = 900 cm, then B = 0.05 cm and P = 1800.1 cm If L = 9000000 cm then B = 0.000005 cm and P = 18000000.00001 cm As can be seen, the perimeter can be increased without limit.