If the original point was (-4, 12) then the image is (-16, 48).
To find the image of point Q under a dilation centered at (0, 0) with a scale factor of 0.5, you multiply the coordinates of Q by 0.5. If Q has coordinates (x, y), the image of Q after dilation will be at (0.5x, 0.5y). This means that the new point will be half the distance from the origin compared to the original point Q.
To find the image of the point (8, -9) after a dilation by a scale factor of 5 from the origin, we multiply each coordinate by 5. This gives us the new coordinates (8 * 5, -9 * 5) = (40, -45). If we then translate this point over the x-axis, we would change the y-coordinate to its opposite, resulting in the final coordinates (40, 45).
similar
None. The vertices, the scale factor as well as the centre of dilation can each be defined independently of the other two. Each different combination will result in a different image.
it is nothing
If the original point was (-4, 12) then the image is (-16, 48).
To find the image of point Q under a dilation centered at (0, 0) with a scale factor of 0.5, you multiply the coordinates of Q by 0.5. If Q has coordinates (x, y), the image of Q after dilation will be at (0.5x, 0.5y). This means that the new point will be half the distance from the origin compared to the original point Q.
Yes, it is.
Because the image is not the same size as the preimage. To do a dilation all you do is make the image smaller or larger than it was before.
Dilation - the image created is not congruent to the pre-image
Dilation
To find the image of the point (8, -9) after a dilation by a scale factor of 5 from the origin, we multiply each coordinate by 5. This gives us the new coordinates (8 * 5, -9 * 5) = (40, -45). If we then translate this point over the x-axis, we would change the y-coordinate to its opposite, resulting in the final coordinates (40, 45).
The image is a similar shape to that of the original.
Image over preimage(original)
Dilation.
With a scale factor of 1, the image is exactly the same size as the original object.